Constrained optimization
Maximize xy subject to x+2y=12, x,y>=0. Substitute x=12-2y, so P(y)=12y-2y^2.
- P'(y)=12-4y; endpoints give zero.
- Apply the method to this new case and check the strongest alternative.
123
02
PRACTICE MISSIONpartial derivatives, gradients, multiple integrals, and optimization
partial derivatives, gradients, multiple integrals, and optimization
Where is the maximum?
MODELSurface Change Viewer
MATH
PROVEChoose with evidence
CLUE
Pause. Find what matters. Then make your move.